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Array sum in C++

To calculate the sum of elements in an array in C++, you can use a loop to iterate through the array and accumulate the values. Here’s a simple example:

C++
#include <iostream>

int main() {
    int arr[] = {1, 2, 3, 4, 5};
    int size = sizeof(arr) / sizeof(arr[0]); // Calculate the size of the array

    int sum = 0;

    // Loop through the array and calculate the sum
    for (int i = 0; i < size; ++i) {
        sum += arr[i];
    }

    std::cout << "Sum of elements in the array: " << sum << std::endl;

    return 0;
}

In this example:

  • We define an integer array arr with some values.
  • We calculate the size of the array using the sizeof operator divided by the size of a single element of the array.
  • We initialize a variable sum to zero to store the sum of elements.
  • We use a for loop to iterate through the array, adding each element to the sum variable.
  • Finally, we print the sum of the elements to the console.

This is a basic example, and you can adapt it to work with arrays of different types and sizes as needed. Additionally, you can use standard library functions like std::accumulate to simplify the sum calculation for more complex cases. Here’s an example using std::accumulate:

C++
#include <iostream>
#include <numeric> // Include the numeric header for std::accumulate

int main() {
    int arr[] = {1, 2, 3, 4, 5};
    int size = sizeof(arr) / sizeof(arr[0]);

    int sum = std::accumulate(arr, arr + size, 0);

    std::cout << "Sum of elements in the array: " << sum << std::endl;

    return 0;
}

The std::accumulate function takes an array or range of elements, starting and ending iterators, and an initial value for accumulation. It simplifies the sum calculation by encapsulating the loop logic.

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